一行简单的fwrite代码在VC2015下面出错，请问是怎么回事

sindy · 2017-12-28 14:25:36

    uint8_t buffer = 0xFF;
    fpRAM = fopen("x.bin", "w+");
    fseek(fpRAM, 0, SEEK_SET);
    fwrite(&buffer, 1024, 10240, fpRAM);

> ucrtbased.dll!write_text_ansi_nolock(const int fh, const char * const buffer, const unsigned int buffer_size) 行 310 C++
ucrtbased.dll!_write_nolock(int fh, const void * buffer, unsigned int buffer_size) 行 576 C++
ucrtbased.dll!_write(int fh, const void * buffer, unsigned int size) 行 63 C++
ucrtbased.dll!_fwrite_nolock(const void * buffer, unsigned __int64 element_size, unsigned __int64 element_count, _iobuf * public_stream) 行 117 C++
ucrtbased.dll!fwrite::__l9::<lambda>() 行 39 C++
ucrtbased.dll!__crt_seh_guarded_call<unsigned __int64>::operator()<void <lambda>(void),unsigned __int64 <lambda>(void) & __ptr64,void <lambda>(void) >(__acrt_lock_stream_and_call::__l3::void <lambda>(void) && setup, fwrite::__l9::unsigned __int64 <lambda>(void) & action, __acrt_lock_stream_and_call::__l4::void <lambda>(void) && cleanup) 行 199 C++
ucrtbased.dll!__acrt_lock_stream_and_call<unsigned __int64 <lambda>(void) >(_iobuf * const stream, fwrite::__l9::unsigned __int64 <lambda>(void) && action) 行 256 C++
ucrtbased.dll!fwrite(const void * buffer, unsigned __int64 size, unsigned __int64 count, _iobuf * stream) 行 41 C++
littlefs.exe!init(...) 行 27 C
littlefs.exe!main() 行 32 C
[外部代码]

sindy · 2017-12-28 14:27:19

晕哥 · 2017-12-28 14:28:27

看起来应该是你定义的buffer太小引起的,
拷贝的时候VC的runtime认为source buffer越界会产生意外，所以保护性出错。
看是不是这样

sindy · 2017-12-28 15:34:49

就是这个问题，搞定，谢谢。

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楼主 #1 2017-12-28 14:25:36 分享评论

一行简单的fwrite代码在VC2015下面出错，请问是怎么回事

楼主 #2 2017-12-28 14:27:19 分享评论

Re: 一行简单的fwrite代码在VC2015下面出错，请问是怎么回事

#3 2017-12-28 14:28:27 分享评论

Re: 一行简单的fwrite代码在VC2015下面出错，请问是怎么回事

楼主 #4 2017-12-28 15:34:49 分享评论

Re: 一行简单的fwrite代码在VC2015下面出错，请问是怎么回事

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